A) \[\left( \frac{1}{2}-\frac{\pi }{360} \right),\left( \frac{1}{2}+\frac{\pi }{360} \right)\]
B) \[\left( \frac{1}{2}-\frac{90}{\pi } \right)\left( \frac{1}{2}+\frac{90}{\pi } \right)\]
C) \[\left( \frac{1}{2}-\frac{\pi }{180} \right),\left( \frac{1}{2}+\frac{\pi }{180} \right)\]
D) None of the above
Correct Answer: B
Solution :
| Let angles in circular measure are A and B, the degree measures will be \[\frac{\pi A}{180{}^\circ }\]and \[\frac{\pi B}{180{}^\circ }\] |
| By given condition, A + B = 1 ... (i) |
| and \[\frac{\pi A}{180{}^\circ }-\frac{\pi B}{180{}^\circ }=1\] ?(ii) |
| On solving Eqs. (i) and (ii), we get |
| \[A=\frac{90{}^\circ }{\pi }\left( \frac{\pi }{180{}^\circ }+1 \right)\]\[\Rightarrow \]\[A=\left( \frac{1}{2}+\frac{90{}^\circ }{\pi } \right)\] |
| From Eq. (i), |
| \[\frac{1}{2}+\frac{90{}^\circ }{\pi }+B=1\] |
| \[\therefore \]\[B=\left( \frac{1}{2}-\frac{90{}^\circ }{\pi } \right)\] |
You need to login to perform this action.
You will be redirected in
3 sec
