A) 2 : 3
B) 4 : 3
C) 5 : 1
D) 5 : 2
Correct Answer: D
Solution :
Let the required ratio be k : 1. |
Then, the point P is \[\left( \frac{4k-3}{k+1},\frac{-\,\,9k+5}{k+1} \right)\] |
\[\therefore \] \[\frac{4k-3}{k+1}=2\] and \[\frac{-\,\,9k+5}{k+1}=-\,\,5\] |
\[\Rightarrow \] \[4k-3=2k+2\] and \[-9k+5=-\,\,5k-5\] |
\[\Rightarrow \] \[2k=5\] and \[4k=10\]\[\Rightarrow \]\[k=\frac{5}{2}\] |
Required ratio is\[\frac{5}{2}:1,\]i.e., 5 : 2. |
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