A) \[50\sqrt{3}\,\,\text{m}\]
B) \[75\,\,\text{m}\]
C) \[25\sqrt{3}\,\,\text{m}\]
D) 25 m
Correct Answer: C
Solution :
Let OG be a height of the tower |
Angle of elevation = Angle of depression |
In \[\Delta FOG,\] |
\[\tan 60{}^\circ =\frac{75}{x}\] |
\[\Rightarrow \] \[x=\frac{75}{\sqrt{3}=25}\sqrt{3}\,\,\text{m}\] |
But OF = OE = OA = OD |
= OC = OB = OA |
= side of hexagon |
\[\therefore \] Length of hexagon \[=25\sqrt{3}\,\,\text{m}\] |
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