A) \[65{}^\circ \]
B) \[55{}^\circ \]
C) \[35{}^\circ \]
D) \[45{}^\circ \]
Correct Answer: B
Solution :
Let \[\angle CDB=x{}^\circ \] Then, \[CD=CB\]\[\Rightarrow \]\[\angle CBD=\angle CDB=x{}^\circ \] \[\angle BCD=\angle BAD=70{}^\circ \] (opposite angles of a rhombus) \[\therefore \]\[x+x+70=180\] (sum of the angles of a triangle is \[180{}^\circ \]) \[\Rightarrow \] \[2x=110\]\[\Rightarrow \]\[x=55\] \[\angle CDB=55{}^\circ .\]You need to login to perform this action.
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