SSC Sample Paper Mock Test-15 SSC CGL Tear-II Paper-1

  • question_answer
    If the sum of \[\frac{a}{b}\]and its reciprocal is 1 and \[a\ne 0,\]\[b\ne 0,\]then the value of \[{{a}^{3}}+{{b}^{3}}\] is

    A) 2

    B)  \[-1\]

    C)  0

    D)  1

    Correct Answer: C

    Solution :

    From the question, \[\frac{a}{b}+\frac{b}{a}=1\] \[\Rightarrow \]   \[{{a}^{2}}+{{b}^{2}}=ab\] \[\Rightarrow \]   \[{{a}^{2}}-ab+{{b}^{2}}=0\] \[\therefore \]      \[{{a}^{3}}+{{b}^{3}}=(a+b)({{a}^{2}}-ab+{{b}^{2}})=0\]


You need to login to perform this action.
You will be redirected in 3 sec spinner