A) 125%
B) 150%
C) 175%
D) 180%
Correct Answer: A
Solution :
Let the edge of the cube be x cm. \[\therefore \]Increased edge \[=x+\frac{x}{2}=\frac{3x}{2}\] Initial surface area\[=6{{x}^{2}}\] Increased surface area \[=6{{\left( \frac{3x}{2} \right)}^{2}}\] Increased m surface area \[=6\left[ \frac{9{{x}^{2}}}{4}-{{x}^{2}} \right]=\frac{6\times 5{{x}^{2}}}{4}\] Percentage increased \[=\frac{30{{x}^{2}}\times 100}{4\times 6{{x}^{2}}}=125%\]
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