SSC Sample Paper Mock Test-15 SSC CGL Tear-II Paper-1

  • question_answer
    If the ratio of volumes of two spheres is 1 : 8, then the ratio of their surface areas is

    A) 1 : 2     

    B)  1 : 4   

    C)  1: 6     

    D)  1 : 8

    Correct Answer: B

    Solution :

    Let the radii of the two spheres be r and R, respectively So,       \[\frac{\frac{4}{3}\pi {{r}^{3}}}{\frac{4}{3}\pi {{R}^{3}}}=\frac{1}{8}\Rightarrow {{\left( \frac{r}{R} \right)}^{3}}=\frac{1}{8}\] \[\therefore \]      \[\frac{r}{R}=\frac{1}{2}\] Now, ratio of surface areas \[=\frac{4\pi {{r}^{2}}}{4\pi {{R}^{2}}}={{\left( \frac{r}{R} \right)}^{2}}={{\left( \frac{1}{2} \right)}^{2}}=\frac{1}{4}\]


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