A) 10
B) \[10\frac{1}{4}\]
C) \[10\frac{1}{2}\]
D) \[10\frac{3}{4}\]
Correct Answer: B
Solution :
Part of the work done by A and B together in 2 days |
\[=\frac{1}{9}+\frac{1}{12}=\frac{4+3}{36}=\frac{7}{36}\] |
Part of the work done in first 10 days |
\[=5\times \frac{7}{36}=\frac{35}{36}\] |
Remaining work \[=1-\frac{35}{36}=\frac{1}{36}\] |
Now, it is turn off A |
\[\therefore \] Time taken by A in doing the remaining part of the work \[=\frac{1}{36}\times 9=\frac{1}{4}\]days |
\[\therefore \] Required time \[=10\frac{1}{4}\]days |
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