A) 2
B) \[-1\]
C) 0
D) 1
Correct Answer: C
Solution :
From the question, \[\frac{a}{b}+\frac{b}{a}=1\] \[\Rightarrow \] \[{{a}^{2}}+{{b}^{2}}=ab\] \[\Rightarrow \] \[{{a}^{2}}-ab+{{b}^{2}}=0\] \[\therefore \] \[{{a}^{3}}+{{b}^{3}}=(a+b)({{a}^{2}}-ab+{{b}^{2}})=0\]You need to login to perform this action.
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