A) 30 cm
B) 35 cm
C) 38 cm
D) 40 cm
Correct Answer: D
Solution :
Area of the field = length \[\times \]breadth \[=12\times 10=120\,\,{{\text{m}}^{2}}\] Area of the pit's surface \[=5\times 4=20\,\,{{\text{m}}^{2}}\] Area on which the Earth is to be spread \[=120-20=100\,\,{{\text{m}}^{2}}\] Volume of Earth dug out \[=5\times 4\times 2=40\,\,{{\text{m}}^{3}}\] \[\therefore \] Level of field raised\[=\frac{40}{100}=\frac{2}{5}\,\,\text{m}\] \[=\frac{2}{5}\times 100=40\,\,\text{cm}\]You need to login to perform this action.
You will be redirected in
3 sec