A) 2
B) 3
C) 4
D) 5
Correct Answer: C
Solution :
Let the numbers be 33a and 33b, where a and b are co-primes. Then, \[33a+33b=528\Rightarrow 33\,\,(a+b)=528\Rightarrow a+b=16\]\[\therefore \] \[(a=1,b=15),\]\[(a=3,b=13),\] \[(a=5,b=11),\]\[(a=7,b=9)\] Numbers are \[(33\times 1,33\times 15),\]\[(33\times 3,33\times 13),\]\[(33\times 5,33\times 11),\]\[(33\times 7,33\times 9)\] Possible number of pairs = 4You need to login to perform this action.
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