A) 4
B) 6
C) 8
D) 15
Correct Answer: C
Solution :
Let all sides of a triangle be a,b and c. |
\[\therefore \] \[a+b+c=40\] |
\[\Rightarrow \] \[a+b=40-17\] \[(\because c=17\,\,cm)\] |
\[\Rightarrow \] \[a+b=23\] ?(i) |
\[\therefore \]Semiperimeter of triangle |
\[(s)=\frac{a+b+c}{2}=\frac{40}{2}=20\,\,\text{cm}\] |
\[\therefore \] Area of triangle \[=\sqrt{s\,\,(s-a)(s-b)(s-c)}\] |
\[\Rightarrow \] \[60=\sqrt{20\,\,(20-a)(20-b)\times 3}\] |
x |
[from Eq.(i)] |
Again, |
?(ii) |
On solving Eqs. (i) and (ii), we get |
Hence, the smallest side is 8 cm. |
You need to login to perform this action.
You will be redirected in
3 sec