SSC Sample Paper Mock Test-16 SSC CGL Tear-II Paper-1

  • question_answer
    The length of the sides of a triangle are in the ratio 3 : 4 : 5 and its perimeter is 144 cm. The area of the triangle is

    A)  \[684\,\,\text{c}{{\text{m}}^{2}}\]

    B)  \[664\,\,\text{c}{{\text{m}}^{2}}\]

    C)  \[764\,\,\text{c}{{\text{m}}^{2}}\]

    D)  \[864\,\,\text{c}{{\text{m}}^{2}}\]

    Correct Answer: D

    Solution :

    Dividing 144 cm in the ratio 3 : 4 : 5, we get a = 36 cm, b = 48 cm, c = 60 Then, \[s=\frac{a+b+c}{2}=\frac{36+48+60}{2}=72\,\,\text{cm}\] \[\therefore \] Area of triangle \[=\sqrt{s\,\,(s-a)(s-b)(s-c)}\] \[=\sqrt{72\times 36\times 24\times 12}\] \[=72\times 12=864\,\,\text{c}{{\text{m}}^{2}}\]


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