A) \[-\,\,1\]
B) 2
C) \[-\,\,2\]
D) 1
Correct Answer: D
Solution :
As, \[\sin x+{{\sin }^{2}}x=1\] ?(i) \[\Rightarrow \] \[\sin x=1-{{\sin }^{2}}x={{\cos }^{2}}x\] \[\therefore \] \[{{\cos }^{2}}x+{{\cos }^{4}}x=(\sin x)+{{\sin }^{2}}x\] \[=1\] [from Eq. (i)]You need to login to perform this action.
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