A) \[100\sqrt{3}\]
B) 50
C) \[\frac{100}{\sqrt{3}}\]
D) 150
Correct Answer: A
Solution :
Let Q and R be the position of two planes. |
Here \[OQ=300\,\,m\] |
In \[\Delta POR,\] |
We have, \[OP=OR\] |
Now, in \[\Delta POQ,\] |
\[\tan 60{}^\circ =\frac{OQ}{OP}=\frac{300}{OR}\] \[(\because OP=OR)\] |
\[\sqrt{3}=\frac{300}{OR}\]\[\Rightarrow \]\[OR=\frac{300}{\sqrt{3}}=100\sqrt{3}\,\,\text{m}\] |
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