A) Rs. 10000 and Rs. 9500
B) Rs. 11500 and Rs. 8000
C) Rs. 12000 and Rs. 7500
D) Rs. 10500 and Rs. 9000
Correct Answer: B
Solution :
Let CP of a horse = Rs. \[x\] |
Then, CP of other horse \[=19500-x\] |
According to the given condition, |
\[x\times \frac{80}{100}=(19500-x)\times \frac{115}{100}\] |
\[\Rightarrow \] \[16x=23\,\,(19500-x)\] |
\[\Rightarrow \] \[16x=448500-23x\]\[\Rightarrow \]\[39x=448500\] |
\[\Rightarrow \] \[x=\frac{448500}{39}\]\[\Rightarrow \]\[x=\]Rs. 11500 |
CP of first horse = Rs. 11500 |
and CP of second horse \[=19500-11500=\text{ }\left( 25\text{ }+\text{ }30\text{ }+\text{ }20\text{ }+\text{ }30\text{ }+\text{ }32.5 \right)\] |
= Rs. 8000 |
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