SSC Sample Paper Mock Test-17 SSC CGL Tear-II Paper-1

The age of a man 10 yr ago was thrice the age of his son. 10 yr hence, the man's age will be twice that of his son. The ratio of their present ages is

A) 13 : 4

B) 9 : 2

C) 7 : 3

D) 5 : 2

Correct Answer: C

Solution :

Let the present age of son be x yr.

Man's age 10 yr ago \[=3(x-10)\] yr\[=(3x-30)\]yr

Man's present age \[=(3x-30+10)\] yr \[=(3x-20)\]yr

Man's age 10 yr hence \[=(3x-20+10)\]yr\[=(3x-10)\] yr

Son's age 10 yr hence \[=(x+10)\]yr

\[\therefore \] \[(3x-10)=2(x+10)\]\[\Rightarrow \]\[x=30\]

Man's present age \[=(3x-20)\] yr = 70 yr

Son's present age = 30 yr.

\[\therefore \]Required ratio = 70 : 30 = 7 : 3