A) \[8\sqrt{2}\,\,\text{cm}\]
B) \[16\,\,\text{cm}\]
C) \[\sqrt{32}\,\,\text{cm}\]
D) \[8\,\,\text{cm}\]
Correct Answer: D
Solution :
Diagonal of square \[=4\sqrt{2}\,\,\text{cm}\] \[\therefore \]Area of square\[=\frac{1}{2}\times {{(4\sqrt{2})}^{2}}=\frac{1}{2}\times 16\times 2=16\,\,\text{c}{{\text{m}}^{2}}\] \[\therefore \] Area of other square\[=2\times 16=32\,\,\text{c}{{\text{m}}^{2}}\] \[\therefore \] Diagonal \[=\sqrt{2\times 32}=8\,\,\text{cm}\]
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