A) 2 : 1
B) 1 : 1
C) 3 : 4
D) \[4:\sqrt{3}\]
Correct Answer: D
Solution :
As a square and an equilateral triangle are drawn on the same base, side of triangle and square will be the same. Let the side be x units. \[\therefore \] \[\frac{\text{Area}\,\,\text{of}\,\,\text{square}}{\text{Area}\,\,\text{of}\,\,\text{triangle}}=\frac{{{x}^{2}}}{\frac{\sqrt{3}}{4}{{x}^{2}}}=\frac{4}{\sqrt{3}}\]
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