A) 12
B) 20
C) 24
D) 48
Correct Answer: D
Solution :
Let the numbers be\[2x,\]\[x\]and \[4x,\]respectively. \[\therefore \] Average \[=\frac{2x+x+4x}{3}\] \[\Rightarrow \] \[\frac{7x}{3}=56\]\[\Rightarrow \]\[x=\frac{3\times 56}{7}=24\] \[\therefore \] First number \[=2x=2\times 24=48\] Third number\[=4x=4\times 24=96\] \[\therefore \] Required difference \[=96-48=48\]You need to login to perform this action.
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