A) 1
B) 0.4087
C) 0.73
D) 0.27
Correct Answer: A
Solution :
Let 0.73 = a and 0.27 = b \[\therefore \] Given expression \[=\frac{{{a}^{3}}+{{b}^{3}}}{{{a}^{2}}+{{b}^{2}}-ab}\] \[=\frac{(a+b)({{a}^{2}}+{{b}^{2}}-ab)}{{{a}^{2}}+{{b}^{2}}-ab}=a+b=0.73+0.27=1\]You need to login to perform this action.
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