A) 8 5 km/h
B) 50 km/h
C) 55 km/h
D) 25 km/h
Correct Answer: A
Solution :
Suppose the speed of first train \[=x\,\,\text{km/h}\] Speed of second train \[=30\,\,\text{km/h}\] \[=\frac{30\times 1000}{60}=500\,\,\text{m/min}\text{.}\] \[\therefore \] According to the question, \[\frac{(66+88)}{x-500}=0.168\] \[\Rightarrow \] \[\frac{154}{x-500}=0.168\] \[\Rightarrow \] \[0.168x-84=154\] \[\Rightarrow \] \[0.168x=238\] \[\Rightarrow \] \[x=\frac{238}{0.168}=\left( \frac{238\times 1000}{168} \right)\text{m/min}\] \[=\frac{238\times 1000}{168}\times \frac{3}{50}\text{km/h}\] \[=85\,\,\text{km/h}\]You need to login to perform this action.
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