A) 30
B) 200
C) 211
D) 249
Correct Answer: D
Solution :
Zeros are obtained if there is any zero at the end of any multiplicand and if 5 or multiple of 5 are multiplied by any even number, i.e.,\[{{(5)}^{n}}{{(2)}^{m}}\] has n zeros if n < m or m zeros if m < n Now, we obtain the index of 5 as follows Index \[=\left[ \frac{1000}{5} \right]+\left[ \frac{1000}{{{5}^{2}}} \right]+\left[ \frac{1000}{{{5}^{3}}} \right]+\left[ \frac{1000}{{{5}^{4}}} \right]\] \[=200+40+8+1=249\] Certainly n will be less than m. \[\therefore \] Number of zeros = 249
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