A) 12 : 5
B) 6 : 5
C) 30 : 19
D) 5 : 3
Correct Answer: C
Solution :
\[x:y=3:2\]\[\Rightarrow \]\[{{x}^{2}}:{{y}^{2}}=9:4\] \[\therefore \]\[\frac{2{{x}^{2}}+3{{y}^{2}}}{3{{x}^{2}}-2{{y}^{2}}}=\frac{2\frac{{{x}^{2}}}{{{y}^{2}}}+3}{3\frac{{{x}^{2}}}{{{y}^{2}}}-2}=\frac{2\times \frac{9}{4}+3}{3\times \frac{9}{4}-2}=\frac{\frac{18+12}{4}}{\frac{27-8}{4}}=30:19\]
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