A) 50
B) 90
C) 100
D) 150
Correct Answer: C
Solution :
Let the Original number of Students in three Classes be 2x, 3x and 5x respectively. As given \[\frac{2x+20}{3x+20}=\frac{4}{5}\] \[\Rightarrow \] \[10x+100=12x+80\] \[\Rightarrow \] \[12x-10x=100-80\] \[\Rightarrow \] \[2x=20\]\[\Rightarrow \]\[x=\frac{20}{2}=10\] \[\therefore \] Total number of students originally \[=2x+3x+5x=10x\] \[=10\times 10=100\]You need to login to perform this action.
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