A) \[3\frac{3}{4}\text{days}\]
B) \[3\frac{3}{7}\text{days}\]
C) \[5\frac{5}{47}\text{days}\]
D) \[4\frac{4}{9}\text{days}\]
Correct Answer: C
Solution :
(A+B)'s 1 day's work \[=\frac{1}{8}\] ...(i) |
(B+C)'s day's work\[=\frac{1}{6}\] ?(ii) |
(C+ A) 's 1 day's work \[=\frac{1}{10}\] ...(iii) |
On adding, = 2(A + B + C)'s |
1 day?s work |
\[=\frac{1}{8}+\frac{1}{6}+\frac{1}{10}=\frac{15+20+12}{120}=\frac{47}{120}\] |
(A + B + C)'s 1 day's work \[=\frac{47}{240}\] |
\[\therefore \] (A + B + C) together will complete the work in |
\[\frac{240}{47}=5\frac{5}{47}\text{days}\] |
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