A) \[\sqrt{pq}\]
B) \[\frac{2pq}{p+q}\]
C) \[\frac{(p+q)}{2}\]
D) \[\frac{1}{2}(p-q)\]
Correct Answer: C
Solution :
Here, as ABCD is trapezium. So, \[EF=\frac{1}{2}(AB+DC)\] \[EF=\frac{1}{2}(p+q)\] \[(\because AB=p,DC=q)\]You need to login to perform this action.
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