A) 2 yr
B) 10 yr
C) \[2\frac{1}{2}\text{yr}\]
D) 15 yr
Correct Answer: B
Solution :
Let their ages be \[3x\] and \[2x\] years \[\therefore \] \[3x-2x=5\] \[x=5\] Age of youngest student \[=2x=2\times 5=10\,\,\text{yr}\]You need to login to perform this action.
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