A) 32 m
B) 8 m
C) 4 m
D) 16 m
Correct Answer: A
Solution :
Let the length and breadth of rectangle be x and metres respectively. |
Then, \[2\,(x+y)=160\] |
\[\Rightarrow \] \[x+y=80\] ...(i) |
and \[x-y=48\] ...(ii) |
Adding Eqs. (i) and (ii), we get |
\[2x=128\] |
\[\Rightarrow \] \[x=\frac{128}{2}=64\] |
From Eq. (i), |
\[y=80-64=16\] |
\[\therefore \] Area \[=64\times 16\]sq m |
\[\therefore \] Area of square \[=\sqrt{64\times 16}=8\times 4=32\,\,\text{m}\] |
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