2. Sample Papers
  3. SSC

SSC Sample Paper Mock Test-18 SSC CGL Tear-II Paper-1

  • question_answer
    Two pipes can fill a cistern in 14 h and 16 h respectively. The pipes are opened simultaneously and it is found that due to leakage in the bottom it took 32 min more to fill the cistern. When the cistern is full, in what time will the leak empty it?

    A) 120 h

    B)  115 h        

    C)  109 h

    D)  112 h   

    Correct Answer: D

    Solution :

    Work done by the two pipes in 1 h
    \[=\left( \frac{1}{14}+\frac{1}{16} \right)=\frac{15}{112}\]
    \[\therefore \]Time taken by these pipes to fill the tank\[=\frac{112}{5}\]h = 7 h 28 min.
    Due to leakage, time taken = 7 h 28 min + 38 min = 8 h
    \[\therefore \]Work done by (two pipes + leak) in 1 h \[=\frac{1}{8}\]
    Work done by the leak in 1 h \[=\left( \frac{15}{112}-\frac{1}{8} \right)=\frac{1}{112}\]
    \[\therefore \] Leak will empty the full cistern in 112 h.


You need to login to perform this action.
You will be redirected in 3 sec spinner