A) 9.3
B) 10.3
C) 11.3
D) 12.3
Correct Answer: C
Solution :
Given expression \[=\frac{10.3\times 10.3\times 10.3+1\times 1\times 1}{10.3\times 10.3-10.3\times 1+1\times 1}\] Let \[10.3=a,\]and \[1=b\] Then, Expression \[=\frac{{{a}^{3}}+{{b}^{3}}}{{{a}^{2}}-ab+{{b}^{2}}}=\frac{(a+b)({{a}^{2}}-ab+{{b}^{2}})}{{{a}^{2}}-ab+{{b}^{2}}}\] \[=a+b=10.3+1=113\]You need to login to perform this action.
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