A) 53.6003
B) 53.603
C) 153.6003
D) 213.0003
Correct Answer: C
Solution :
| \[47.2506=40+7+\frac{2}{10}+\frac{5}{100}+\frac{0}{1000}+\frac{6}{10000}\] |
| \[4A=40,\] \[\frac{7}{B}=7,\] |
| \[2C=\frac{2}{10},\] \[\frac{5}{D}=\frac{5}{100},\] |
| \[6E=\frac{6}{10000}\] |
| \[\therefore \]\[A=10,\]\[B=1,\]\[C=\frac{1}{10},\]\[D=100,\]\[E=\frac{1}{10000}\] |
| \[\therefore \]\[(5A+3B+6C+D+3E)\] |
| \[=\left( 5\times 10+3\times 1+6\times \frac{1}{10}+100+3\times \frac{1}{10000} \right)\] |
| \[=(50+3+0.6+100+0.0003)=153.6003\] |
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