A) 24 days
B) 25 days
C) 30 days
D) 32 days
Correct Answer: A
Solution :
Work done by A in 15 days\[=\frac{1}{60}\times 15=\frac{1}{4}\] |
Remaining work \[=\left( 1-\frac{1}{4} \right)=\frac{3}{4}\] |
Now, \[\frac{3}{4}\]work is done by B in 30 days. |
\[\therefore \] Whole work will be done by B in |
\[\frac{30\times 4}{3}=40\,\,\text{days}\] |
\[\therefore \] A's 1 day's work \[=\frac{1}{60}\] |
and B's 1 day's work \[=\frac{1}{40}\] |
\[\therefore \] (A + B)'s 1 day's work |
\[=\frac{1}{60}+\frac{1}{40}=\frac{2+3}{120}=\frac{5}{120}=\frac{1}{24}\] |
Hence, both will finish the work in 24 days. |
You need to login to perform this action.
You will be redirected in
3 sec