A) 15 days
B) 20 days
C) 25 days
D) 30 days
Correct Answer: C
Solution :
A's 1 day's work = (B + C)'s 1 day's work (A+ B)'s 1 day's work\[=\frac{1}{10}\] C's day's work \[=\frac{1}{50}\] \[\therefore \] (A+B+C)'s 1 day's work \[=\frac{1}{10}+\frac{1}{50}=\frac{5+1}{50}\] \[=\frac{6}{50}=\frac{3}{25}\] \[\therefore \] (A+A)'s 1 day's work \[=\frac{3}{25}\] \[\therefore \] A's 1 day's work \[=\frac{3}{50}\] \[\therefore \]B's 1 day?s work \[=\frac{1}{10}-\frac{3}{50}=\frac{5-3}{50}=\frac{2}{50}=\frac{1}{25}\] Hence, B alone will complete the work in 25 days.You need to login to perform this action.
You will be redirected in
3 sec