A) 20
B) 24
C) 30
D) 36
Correct Answer: C
Solution :
Suppose amount received by men \[=5x\] |
and amount received by women \[=4x\] |
According to the question, |
\[5x+4x=180\]\[\Rightarrow \]\[9x=180\]\[\Rightarrow \]\[x=20\] |
\[\therefore \] Amount received by men = Rs. 100 |
Amount received by women = Rs. 80 |
Suppose the number of men be y and that of women be \[(66-y).\] |
According to the question, \[\frac{\frac{100}{y}}{\frac{80}{66-y}}=\frac{3}{2}\] |
\[\Rightarrow \] \[\frac{100}{y}\times \frac{66-y}{80}=\frac{3}{2}\] |
\[\Rightarrow \] \[\frac{5\,\,(66-y)}{4y}=\frac{3}{2}\] |
\[\Rightarrow \] \[660-10y=12y\] |
\[\Rightarrow \] \[22y=660\] |
\[\therefore \] \[y=30\] |
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