A) \[\frac{20}{21}\]
B) \[-\frac{21}{20}\]
C) \[\frac{21}{20}\]
D) \[-\frac{20}{21}\]
Correct Answer: C
Solution :
Here, |
\[\frac{\frac{1}{4}-\frac{1}{6}-\frac{1}{48}}{\frac{1}{4}-\left( \frac{1}{6}-\frac{1}{48} \right)}\div \frac{\frac{1}{4}\times \frac{1}{6}-\frac{1}{48}}{\frac{1}{4}\times \left( \frac{1}{6}-\frac{1}{48} \right)}=x\] |
\[\Rightarrow \]\[x=\frac{\frac{12-8-1}{48}}{\frac{12-(8-1)}{48}}\div \frac{\frac{1}{24}-\frac{1}{48}}{\frac{1}{4}\times \left( \frac{8-1}{48} \right)}\] |
\[\therefore \]\[x=\frac{\frac{3}{48}}{\frac{5}{48}}\div \frac{\frac{2-1}{48}}{\frac{7}{4\times 48}}\] |
\[=\frac{3}{5}\div \frac{4}{7}=\frac{21}{20}\] |
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