A) 12
B) 8
C) 14
D) 16
Correct Answer: B
Solution :
(A+B)?s 1 day?s work \[=\frac{1}{8}\] |
(B+C)?s 1day?s work \[=\frac{1}{12}\] |
(C+A)?s1 day?s work\[=\frac{1}{x}\] |
\[\therefore \](A+B+C)?s 1 day?s work \[=\frac{1}{2}\left[ \frac{1}{8}+\frac{1}{12}+\frac{1}{x} \right]\] |
\[\left( \frac{1}{6} \right)=\frac{1}{2}\left[ \frac{1}{8}+\frac{1}{12} \right]+\frac{1}{2x}\] |
\[\Rightarrow \] \[\frac{1}{x}=\frac{1}{3}-\left( \frac{1}{8}+\frac{1}{12} \right)=\frac{3}{24}=\frac{1}{8}\] |
So, C and A can do the work in 8 days. |
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