A) \[6\frac{1}{8}\]
B) \[6\frac{3}{4}\]
C) \[7\frac{3}{4}\]
D) \[7\frac{5}{6}\]
Correct Answer: B
Solution :
Required excess \[=\frac{6}{7/8}-\frac{6/7}{8}=\frac{6\times 8}{7}-\frac{6}{7\times 8}=\frac{48}{7}-\frac{6}{56}\] \[=\frac{48}{7}-\frac{3}{28}=\frac{(192-3)}{28}=\frac{189}{28}=\frac{27}{4}=6\frac{3}{4}\]You need to login to perform this action.
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