A) Zero
B) Only 1
C) Only 2
D) Many
Correct Answer: A
Solution :
HCF of two numbers = 16 and LCM of two number = 146 Let the first number, y =16 a and the second number, y = 16 b We know that, HCF \[\times \]LCM= product of two numbers \[\Rightarrow \]\[16\times 146=x\times y\]\[\Rightarrow \]\[16\times 146=16a\times 16b\] \[\Rightarrow \] \[a\times b=\frac{146}{16}=9.125\] The number of such pairs is zero, since \[a\times b\]is not integer.You need to login to perform this action.
You will be redirected in
3 sec