A) 1
B) \[-\,\,1\]
C) 2
D) \[-\,\,2\]
Correct Answer: A
Solution :
Here, \[f(x)=12{{x}^{3}}-13{{x}^{2}}-5x+7\] |
Put \[3x+2=0\] |
\[\Rightarrow \] \[x=\frac{-2}{3}\] |
\[f\left( \frac{-\,\,2}{3} \right)=12{{\left( \frac{-\,\,2}{3} \right)}^{3}}-13{{\left( \frac{-\,\,2}{3} \right)}^{2}}-5\times \frac{-\,\,2}{3}+7\] |
\[=\frac{-96}{27}-\frac{52}{9}+\frac{10}{3}+7\] |
\[=\frac{-\,\,32}{9}-\frac{52}{9}+\frac{10}{3}+7\] |
\[=\frac{-\,\,32-52+30+63}{9}=\frac{-\,\,84+93}{9}=\frac{9}{9}=1\] |
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