A) 5 : 7
B) 7 : 5
C) 3 : 4
D) 4 : 3
Correct Answer: B
Solution :
Let 1 kg of each one of A and B be taken to form 2 kg of C. |
\[\therefore \]Gold in 1 kg of A \[=\frac{7}{9}\] |
Copper in 1 kg of A \[=\frac{2}{9}\] |
Gold in 1 kg of B \[=\frac{7}{18}\] |
Pepper in 1 kg of B \[=\frac{11}{18}\] |
Gold in 2 kg of |
C\[=\left( \frac{7}{9}+\frac{7}{18} \right)=\frac{14+7}{18}=\frac{21}{18}=\frac{7}{6}\] |
Copper in 2 kg of |
C \[=\left( \frac{2}{9}+\frac{11}{18} \right)=\left( \frac{4+11}{18} \right)=\frac{15}{18}=\frac{5}{6}\] |
\[\therefore \]Ratio of gold and copper in C\[=\frac{7}{6}:\frac{5}{6}=7:5\] |
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