A) Rs. 3000
B) Rs. 3300
C) Rs. 3500
D) Rs.3800
Correct Answer: A
Solution :
Let the cost of one chair = Rs. x |
and cost of one table = Rs. y |
By given condition, |
\[10x+6y=6200\] ?(i) |
and \[3x+2y=1900\] |
\[\Rightarrow \] \[9x+6y=5700\] ?(ii) |
On subtracting Eq. (ii) from Eq. (i), we get |
x = Rs. 500 |
From Eq. (i), |
\[5000+6y=6200\] |
\[\Rightarrow \] \[6y=1200\] |
\[y=200\] |
\[\therefore \]The cost of 4 chairs and 5 tables |
\[=4x+5y=4\times 500+5\times 200\] |
\[=2000+1000=\] Rs. 3000 |
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