A) \[\frac{1}{3}\]
B) \[\frac{2}{3}\]
C) \[\frac{5}{6}\]
D) \[\frac{1}{6}\]
Correct Answer: D
Solution :
Hence, \[n\,\,(S)=6\times 6=36\] Now suppose E = Event of getting a sum of 7 =(1, 7), (2, 5), (3, 4), (4, 3), (5, 2) and (6, 1) = 6 So, \[P\,\,(E)=\frac{n\,\,(E)}{n\,\,(S)}=\frac{6}{36}=\frac{1}{6}\]You need to login to perform this action.
You will be redirected in
3 sec