A) 5
B) 3
C) 2
D) 1
Correct Answer: D
Solution :
Putting \[(a-b)=x,\]\[(b-c)=y\]and \[(c-a)=z,\] we get \[x+y+z=0\] \[\therefore \] \[{{x}^{3}}+{{y}^{3}}+{{z}^{3}}=3xyz\] \[\therefore \] Given expression \[=\frac{{{x}^{3}}+{{y}^{3}}+{{z}^{3}}}{6xyz}=\frac{3xyz}{6xyz}=\frac{1}{2}\]You need to login to perform this action.
You will be redirected in
3 sec