A) 105
B) 99
C) 108
D) 105
Correct Answer: C
Solution :
Given expression \[=\frac{{{a}^{3}}+{{b}^{3}}+{{c}^{3}}-3abc}{{{a}^{2}}+{{b}^{2}}-ab-bc-ca},\]where \[a=47,\]\[b=35,\]\[c=26\] \[=(a+b+c)=(47+35+26)=108\]You need to login to perform this action.
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