A) 0
B) 1
C) \[-\,\,1\]
D) \[\frac{27}{2}\]
Correct Answer: D
Solution :
\[x-\frac{1}{x}=\frac{1}{2}\] On squaring, we get \[{{x}^{2}}+\frac{1}{{{x}^{2}}}-2=\frac{1}{4}\] \[{{x}^{2}}+\frac{1}{{{x}^{2}}}=\frac{1}{4}+2=\frac{9}{4}\] \[\Rightarrow \] \[6\left( {{x}^{2}}+\frac{1}{{{x}^{2}}} \right)=6\times \frac{9}{4}=\frac{27}{2}\]You need to login to perform this action.
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