A) 1
B) \[\frac{1}{2}\]
C) \[\frac{1}{\sqrt{2}}\]
D) \[0\]
Correct Answer: C
Solution :
As, \[3\sin \theta -4{{\sin }^{3}}\theta =\sin 3\theta \] So, \[3\sin 15{}^\circ -4{{\sin }^{3}}15{}^\circ =\sin 3\,\,(15){}^\circ =\sin 45{}^\circ =\frac{1}{\sqrt{2}}\]You need to login to perform this action.
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