A) 1
B) \[-\,\,\sqrt{2}\]
C) \[\sqrt{2}\]
D) \[-1\]
Correct Answer: C
Solution :
The maximum value of \[a\sin \theta +b\cos \theta \] is \[\sqrt{{{a}^{2}}+{{b}^{2}}}.\] So, here a = 1, A = 1 Maximum value \[=\sqrt{1+1}=\sqrt{2}\]You need to login to perform this action.
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