SSC Sample Paper Mock Test-3 SSC CGL Tear-II Paper-1

  • question_answer
    If \[\frac{2a+b}{a+4b}=3,\]then find the value of\[\frac{a+b}{a+2b}\]

    A)  \[\frac{5}{9}\]                         

    B)  \[\frac{2}{7}\]

    C)  \[\frac{10}{9}\]

    D)  \[\frac{10}{7}\]

    Correct Answer: C

    Solution :

    \[\frac{2a+b}{a+4b}=3\]                                  (Given) \[\Rightarrow \]   \[2a+b=3a+12b\] \[\Rightarrow \]   \[3a-2a=b-12b\] \[\Rightarrow \]   \[a=-11b\] Then,    \[\frac{a+b}{a+2b}=\frac{-11b+b}{-11b+2b}=\frac{-10b}{-9b}=\frac{10}{9}\]                        


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