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SSC Sample Paper Mock Test-3 SSC CGL Tear-II Paper-1

  • question_answer
    A wire when bent in the form of a square encloses an area of 484 sq cm. What will be the enclosed area when the same wire is bent into the form of a circle? (Take \[\pi =\frac{22}{7}\])

    A)  462 sq cm                    

    B)  539 sq cm

    C)  616 sq cm

    D)  693 sq cm

    Correct Answer: C

    Solution :

    Area of the square\[={{(side)}^{2}}\] \[484={{(side)}^{2}}\] Side \[=\sqrt{484}=22\,\text{cm}\] \[\therefore \]Perimeter of the square \[=4\times \] side\[=4\times 22=88\,\,\text{cm}\] According to the question, the circle is made by same wire. Therefore, Perimeter of the square = Circumference of Ac circle \[88\,\,\text{cm}=2\pi r\] \[88\,\text{cm}=2\times \frac{22}{7}\times r\] \[\therefore \]                  \[r=\frac{88\times 7}{2\times 22}=14\,\text{cm}\] \[\therefore \]Area of circle \[=\pi {{r}^{2}}=\frac{22}{7}\times {{(14)}^{2}}=\frac{22}{7}\times 14\times 14\] = 616 sq cm                        


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